x^-2=1/35

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Solution for x^-2=1/35 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x^-2 = 1/35 // - 1/35

x^-2-(1/35) = 0

x^-2-1/35 = 0

1*x^-2 = 1/35 // : 1

x^-2 = 1/35

-2 < 0

1/(x^2) = 1/35 // * x^2

1 = 1/35*x^2 // : 1/35

35 = x^2

x^2 = 35 // ^ 1/2

abs(x) = 35^(1/2)

x = 35^(1/2) or x = -35^(1/2)

x in { 35^(1/2), -35^(1/2) }

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